PHOTOSYNTHESIS
THE CALVIN CYCLE
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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How many molecules are present in reduction that ATP and NADPH reduce? (HINT:Reuben is cut in half!)
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1
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2
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3
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4
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Explanation:
Detailed explanation-1: -For one turn: ATP used = 3 molecules NADPH used = 2 molecules Thus for six cycles : ATP used = 3*6 = 18 molecules NADPH used = 2*6 = 12 molecules Therefore total ATP and NADPH required to produce one molecule of glucose is 18 and 12 respectively.
Detailed explanation-2: -For the synthesis of one glucose molecule, 6 Calvin cycles are necessary and a total of 18 ATP, 12 NADPH are consumed in 6 Calvin cycles. So, for the synthesis of 2 glucose molecules 36 ATP, 24 NADPH and 12 turns of Calvin cycle are needed.
Detailed explanation-3: -For every molecule of CO2 entering the Calvin cycle, 3 molecules of ATP and 2 molecules of NADPH are used.
Detailed explanation-4: -24 ATP, 36 NADPH, 12 Calvin cycles.
There is 1 question to complete.