AP BIOLOGY

PHOTOSYNTHESIS

THE CALVIN CYCLE

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Which of the following best describes what occurs during the reduction stage of the Calvin cycle?
A
NADH is used to transform 3-bisphosphoglycerate into 1, 3-phosphoglycerate . Which then reduces 1, 3-phosphoglycerate with the addition of NADH+ to form PGA
B
NADPH is used to transform 3-phosphoglycerate into 1, 3 bisphosphoglycerate are reduced with the addition of ATP to form G3P.
C
ATP is used to transform 3-bisphosphoglycerate into 1, 3-phosphoglycerate . Which then reduces 1, 3-phosphoglycerate with the addition of NADPH to form PGA.
D
ATP is used to transform 3-phosphoglycerate into 1, 3 bisphosphoglycerate. Which then 1 3-bisphosphoglycerate are reduced with the addition of NADPH to form G3P.
Explanation: 

Detailed explanation-1: -Reduction. It is the second stage of Calvin cycle. The 3-PGA molecules created through carbon fixation are converted into molecules of simple sugar – glucose. This stage obtains energy from ATP and NADPH formed during the light-dependent reactions of photosynthesis.

Detailed explanation-2: -Reduction. In the second stage, ATP and NADPH are used to convert the 3-PGA molecules into molecules of a three-carbon sugar, glyceraldehyde-3-phosphate (G3P). This stage gets its name because NADPH donates electrons to, or reduces, a three-carbon intermediate to make G3P.

Detailed explanation-3: -1, 3-Bisphosphoglycerate is then reduced by glyceraldehyde 3-phosphate dehydrogenase using NADPH to form glyceraldehyde 3-phosphate (GAP, a triose or 3C sugar) in reactions, which are the reverse of glycolysis.

Detailed explanation-4: -Light energy is converted to chemical energy.

There is 1 question to complete.