AP BIOLOGY

THE MOLECULAR BASIS OF INHERITANCE

DNA REPLICATION

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What happens during the formation of Okazaki fragments?
A
DNA polymerase I adds nucleotides in the 5´
B
RNA polymerase adds nucleotides in the 3´
C
DNA polymerase III adds nucleotides in the 5´
D
DNA polymerase III adds nucleotides in the 3´
Explanation: 

Detailed explanation-1: -Okazaki fragments are initiated by creation of a new RNA primer by the primosome. To restart DNA synthesis, the DNA clamp loader releases the lagging strand from the sliding clamp, and then reattaches the clamp at the new RNA primer. Then DNA polymerase III can synthesize the segment of DNA.

Detailed explanation-2: -DNA polymerases can only make DNA in the 5’ to 3’ direction, and this poses a problem during replication. A DNA double helix is always anti-parallel; in other words, one strand runs in the 5’ to 3’ direction, while the other runs in the 3’ to 5’ direction.

Detailed explanation-3: -The need for accuracy probably explains why DNA replication occurs only in the 5′-to-3′ direction. If there were a DNA polymerase that added deoxyribonucleoside triphosphates in the 3′-to-5′ direction, the growing 5′-chain end, rather than the incoming mononucleotide, would carry the activating triphosphate.

Detailed explanation-4: -DNA polymerase is able to add nucleotides only in the 5’ to 3’ direction (a new DNA strand can be only extended in this direction). It also requires a free 3’-OH group to which it can add nucleotides by forming a phosphodiester bond between the 3’-OH end and the 5’ phosphate of the next nucleotide.

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