THE MOLECULAR BASIS OF INHERITANCE
RECOMBINANT DNA
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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5‘-CTAAGC-3‘3‘-GATTCG-5‘
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5’-TTCCTT-3’3’-AAGGAA-5’
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5’-GAATTC-3’3’-CTTAAG-5’
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5’-TCAGTC-3’3’-AGTCAG-5’
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Detailed explanation-1: -Restriction enzymes can create fragments with sticky ends, as is the case with the enzyme BamHI, or blunt ends, as with HaeIII (Table 8.1). Double bars indicate the cleavage site in the DNA strand. DNA ligases are used to join the fragments of DNA generated by restriction enzymes.
Detailed explanation-2: -So, the correct option is ‘GGCC CCGG’. Was this answer helpful?
Detailed explanation-3: -Restriction endonucleases cleave double-stranded DNA. These enzymes are sequence specific, and each enzyme acts at a limited number of sites in DNA called recognition, or cutting, sites.
Detailed explanation-4: -A ‘sticky’ end is produced when the restriction enzyme cuts at one end of the sequence, between two bases on the same strand, then cuts on the opposite end of the complementary strand. This will produce two ends of DNA that will have some nucleotides without any complementary bases.