THE MOLECULAR BASIS OF INHERITANCE
THE GENETICS OF VIRUSES AND BACTERIA
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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5’-TGA AGA CCG-3’
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5’-UGA AGA CCG-3’
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3’-CGG UCU UCA-5’
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3’-ACU UCU GGC-5’
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Detailed explanation-1: -If the DNA segment is 5′-TGA AGA CCG-3′, then the mRNA strand complementary to that is 3′-ACU UCU GGC-5′.
Detailed explanation-2: -DNA is always synthesized in the 5’-to-3’ direction, meaning that nucleotides are added only to the 3’ end of the growing strand. As shown in Figure 2, the 5’-phosphate group of the new nucleotide binds to the 3’-OH group of the last nucleotide of the growing strand.
Detailed explanation-3: -Answer and Explanation: The codon in mRNA that corresponds to the sequence 5’-AGT-3’ in the DNA template is 3’-UCA-5’ which also can be written as 5’-ACU-3’.
Detailed explanation-4: -Solution : ‘5’ to 3 “ is the direction of synthesis of mRNA on DNA template.
Detailed explanation-5: -RNA polymerase synthesizes an RNA transcript complementary to the DNA template strand in the 5’ to 3’ direction. It moves forward along the template strand in the 3’ to 5’ direction, opening the DNA double helix as it goes.