CELL RESPIRATION
GLYCOLYSIS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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Citric Acid (6C)
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Fumaric Acid (4C)
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Malic Acid (4C)
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a-Ketoglutaric Acid (5C)
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Detailed explanation-1: -Krebs cycle starts with condensation of acetyl-CoA with oxaloacetate (OAA, 4C) to form citrate (6C) and is catalyzed by enzyme citrate synthase. Link reaction of aerobic respiration decarboxylates pyruvic acid into acetyl CoA which in turn enters Krebs’s cycle.
Detailed explanation-2: -The Krebs cycle starts with condensation of acetyl group with oxaloacetic acid (OAA) and water to yield citric acid. This reaction is catalysed by the enzyme citrate synthase and a molecule of CoA is released.
Detailed explanation-3: -Complete Answer: Oxaloacetic acid is a 4C compound that takes part in the tricarboxylic acid cycle. The Kreb cycle was first discovered by Sir Hans Krebs in 1937.
Detailed explanation-4: -So, the correct answer is ‘Oxaloacetic acid’.
Detailed explanation-5: -Explanation: Acetyl CoA formed from pyruvic acid enters Krebs’ cycle by combining with oxaloacetic acid. OAA and acetyl CoA form a 6-carbon compound citric acid as first product of the cycle. So, the correct answer is ‘Citrate’.