AP BIOLOGY

Detailed explanation-1: -In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.

Detailed explanation-2: -If the homozygous recessive genotype makes of 16% of the population the fraction of the recessive allele is the square root of the q (recessive allele fraction )= √¯ 0.16 = 0.4. The dominant allele is 1-p = 1-0.4 = 0.6.

Detailed explanation-3: -The Hardy-Weinberg Equation q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype. p2 = the frequency of homozygous dominant genotype. q2 = the frequency of homozygous recessive genotype.

Detailed explanation-4: -In a certain population which is in Hardy-Weinberg equilibrium, there are only two eye colours: brown (dominant) and blue (recessive). 16 % have blue eyes in the population.