AP BIOLOGY

Detailed explanation-1: -So, the correct answer is ‘0.64’

Detailed explanation-2: -The Hardy-Weinberg Equation q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype. p2 = the frequency of homozygous dominant genotype. q2 = the frequency of homozygous recessive genotype.

Detailed explanation-3: -In a population that is in Hardy-Weinberg equilibrium, 38 % of the individuals are recessive homozygotes for a certain trait.

Detailed explanation-4: -The frequency of homozygous pp individuals is p2; the frequency of hereozygous pq individuals is 2pq; and the frequency of homozygous qq individuals is q2. If p and q are the only two possible alleles for a given trait in the population, these genotypes frequencies will sum to one: p2 + 2pq + q2 = 1.

Detailed explanation-5: -In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.