EVOLUTION
HARDY WEINBERG EQUILIBRIUM
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
|
hilarious genotype
|
|
heterozygous genotype
|
|
the homozygous recessive genotype
|
|
the homozygous dominant genotype
|
Detailed explanation-1: -We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09. Thus, p = 1 – q ∴ p = 1 – 0.30 = 0.70 ∴The homozygote dominants are represented by p2 = (0.70)2 = 0.49 or 49% Page 2 4.
Detailed explanation-2: -p = frequency of the dominant allele in the population. q = frequency of the recessive allele in the population. p2 = percentage of homozygous dominant individuals. q2 = percentage of homozygous recessive individuals. 2pq = percentage of heterozygous individuals.
Detailed explanation-3: -In the simplest system, with two alleles of the same locus (e.g. A, a), we use the symbol p to represent the frequency of the dominant allele within the population, and q for the frequency of the recessive allele.
Detailed explanation-4: -The frequency of genotypes in a population can be represented by p2+2pq+q2= 1, with p2 equal to the frequency of the homozygous dominant genotype, 2pq equal to the frequency of the heterozygous genotype, and q2 equal to the frequency of the recessive genotype.