EVOLUTION
HARDY WEINBERG EQUILIBRIUM
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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If there are 10 people, 5 of them have Bb, 3 of them have BB and 2 of the have bb, what is the frequency for p and q?
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p= 0.55 q=0.45
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p=0.5 q=0.6
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p=0.3 q= 0.7
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p=0.25 q=0.75
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Explanation:
Detailed explanation-1: -To find q, simply take the square root of 0.09 to get 0.3. Since p = 1-0.3, then p must equal 0.7. 2pq = 2 (0.7 x 0.3) = 0.42 = 42% of the population are heterozygotes (carriers).
Detailed explanation-2: -Hardy-Weinberg Equations The variable ‘p2’ denotes the homozygous dominant genotype (AA), ‘2pq’ denotes the heterozygous genotype (Aa), and ‘q2’ denotes the homozygous recessive genotype (aa). The following conclusions can be inferred through this law: Only sexual reproduction is possible. Mating is a random process.
Detailed explanation-3: -In this equation,
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