EVOLUTION
HARDY WEINBERG EQUILIBRIUM
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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p
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p2
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q
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q2
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2pq
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Detailed explanation-1: -Calculate the percentage of individuals homozygous for the dominant allele. We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09. Thus, p = 1 – q ∴ p = 1 – 0.30 = 0.70 ∴The homozygote dominants are represented by p2 = (0.70)2 = 0.49 or 49% Page 2 4.
Detailed explanation-2: -In a certain population which is in Hardy-Weinberg equilibrium, there are only two eye colours: brown (dominant) and blue (recessive). 16 % have blue eyes in the population.
Detailed explanation-3: -In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.
Detailed explanation-4: -1 = p2 + 2pq + q2 P and q each represent the allele frequency of different alleles. The term p2 represents the frequency of the homozygous dominant genotype.