AP BIOLOGY

Detailed explanation-1: -In this case, 2pq equals 0.32, which means that the frequency of individuals heterozygous for this gene is equal to 32% (i.e. 2 (0.8)(0.2) = 0.32).

Detailed explanation-2: -Count up the aa types and you have the observed q2. Then, take the square root of q2 to get q, and then subtract q from 1 to get p. Square p to get p2 and multiply 2*p*q to get the observed heterozygous Aa genotype frequency.

Detailed explanation-3: -We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09.

Detailed explanation-4: -In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.