EVOLUTION
HARDY WEINBERG EQUILIBRIUM
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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.80
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.04
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.32
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.64
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Detailed explanation-1: -The frequency of heterozygous individuals. Answer: The frequency of heterozygous individuals is equal to 2pq. In this case, 2pq equals 0.32, which means that the frequency of individuals heterozygous for this gene is equal to 32% (i.e. 2 (0.8)(0.2) = 0.32).
Detailed explanation-2: -Expected heterozygosity (Hexp = 2pq) for a 2-allele system as a function of allele frequency, p. Note that the heterozygosity peaks at a value of 0.5, when the allele frequencies are equal (p=q). It is minimal at both extremes–in those cases everyone is a homozygote of one type or the other.
Detailed explanation-3: -An allele frequency is calculated by dividing the number of times the allele of interest is observed in a population by the total number of copies of all the alleles at that particular genetic locus in the population. Allele frequencies can be represented as a decimal, a percentage, or a fraction.
Detailed explanation-4: -Another aspect of alleles and segregation is the concept of allele frequencies within a population. On an individual level, a person has a 0.5 chance of passing on one of two alleles for a given gene.