AP BIOLOGY

EVOLUTION

HARDY WEINBERG EQUILIBRIUM

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
In a population of cats, short hair is dominant to long hair. If 16% of a breeder’s cats have short hair, what is the frequency of the recessive allele?
A
0.08
B
.4
C
0.6
D
.92
Explanation: 

Detailed explanation-1: -The “2pq” in equation shows frequency of heterozygotes in the population. In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.

Detailed explanation-2: -In a certain population which is in Hardy-Weinberg equilibrium, there are only two eye colours: brown (dominant) and blue (recessive). 16 % have blue eyes in the population.

Detailed explanation-3: -In cats, the allele for short hair (S) is dominant over the allele for long hair (or Angora) (s). A short-haired tomcat is mated with an Angora female. She bears seven kittens; four short-haired and three Angora.

Detailed explanation-4: -The gene carrying the long hair trait in cats is recessive. That means the result of a shorthaired cat mating with a longhaired will only be shorthaired kittens. However, if the shorthaired offspring were to mate with each other, a handful of longhaired kittens might be born.

There is 1 question to complete.