EVOLUTION
HARDY WEINBERG EQUILIBRIUM
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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0.08
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.4
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0.6
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.92
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Detailed explanation-1: -The “2pq” in equation shows frequency of heterozygotes in the population. In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.
Detailed explanation-2: -In a certain population which is in Hardy-Weinberg equilibrium, there are only two eye colours: brown (dominant) and blue (recessive). 16 % have blue eyes in the population.
Detailed explanation-3: -In cats, the allele for short hair (S) is dominant over the allele for long hair (or Angora) (s). A short-haired tomcat is mated with an Angora female. She bears seven kittens; four short-haired and three Angora.
Detailed explanation-4: -The gene carrying the long hair trait in cats is recessive. That means the result of a shorthaired cat mating with a longhaired will only be shorthaired kittens. However, if the shorthaired offspring were to mate with each other, a handful of longhaired kittens might be born.