# AP BIOLOGY

## EVOLUTION

### HARDY WEINBERG EQUILIBRIUM

 Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What part of the Hardy Weinberg formula is used to determine the allele frequency of homozygous dominant genotypes (AA)?
 A p2 B 2pq C q2
Explanation:

Detailed explanation-1: -Then, take the square root of q2 to get q, and then subtract q from 1 to get p. Square p to get p2 and multiply 2*p*q to get the observed heterozygous Aa genotype frequency. Conclusion: If observed and expected genotype frequencies are significantly different, the population is out of HWE.

Detailed explanation-2: -The Hardy-Weinberg Equation p = the frequency of the dominant allele in a population. q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype. p2 = the frequency of homozygous dominant genotype.

Detailed explanation-3: -In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.

Detailed explanation-4: -The frequency of genotypes in a population can be represented by p2+2pq+q2= 1, with p2 equal to the frequency of the homozygous dominant genotype, 2pq equal to the frequency of the heterozygous genotype, and q2 equal to the frequency of the recessive genotype.

Detailed explanation-5: -The frequency of the “aa” genotype. Answer: 36%, as given in the problem itself. The frequency of the “a” allele. Answer: The frequency of aa is 36%, which means that q2 = 0.36, by definition.

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