EVOLUTION
HARDY WEINBERG EQUILIBRIUM
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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.5625
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.3750
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.0625
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.25
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Detailed explanation-1: -The frequency of heterozygous individuals. Answer: The frequency of heterozygous individuals is equal to 2pq. In this case, 2pq equals 0.32, which means that the frequency of individuals heterozygous for this gene is equal to 32% (i.e. 2 (0.8)(0.2) = 0.32).
Detailed explanation-2: -So, the correct answer is ‘0.64’
Detailed explanation-3: -In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.
Detailed explanation-4: -As given, the frequency of a recessive phenotype is 25% (tt). So 25% is the phenotypic ratio of 3:1 of the F2 generation of a monohybrid cross. Therefore, the frequency of the dominant phenotype will be 75%.