HEREDITY
LINKAGE MAPPING
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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If the distance between A/B is 0.12 mu and gene C is on the opposite side of A with respect to B at a distance of 0.23 mu, then distance A/C is (choose the most accurate option)
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equal to 0.35 mu
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greater than 0.35 mu
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lesser than 0.35 mu
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equal to or lesser than 0.35 mu
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equal to or greater than 0.35 mu
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Explanation:
Detailed explanation-1: -∙ The more the distance between the gene on chromosomes, then gene shows weak linkage and follow crossing over to form new combination of genetic material and the less the distance between the genes the greater the linkage.
Detailed explanation-2: -The genetic distance between genes A and B is 10 cM. An organism with Ab combination of the alleles is crossed with the organism with aB combination of alleles.
Detailed explanation-3: -If the distance between the genes is more, then the genes are loosely linked and there is a greater chance of crossing over.
Detailed explanation-4: -Genes independently assort at a distance of 50 cM or more apart.
There is 1 question to complete.