LABORATORY REVIEW
MOLECULAR BIOLOGY
|
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
How many moles of KI are present in 0.85 L of a 0.55 M KI solution?
|
|
3.10 mols
|
|
|
0.935 mols
|
|
|
0.4675 mols
|
|
|
1.55 mols
|
Explanation:
Detailed explanation-1: -Answer. Therefore, there are 0.4675 moles of KI of 0.85L of a 0.55 M KI solution.
Detailed explanation-2: -WHAT IS MOLARITY? Therefore, there are 0.4675 moles of KI in 0.85L of a 0.55 M KI solution.
Detailed explanation-3: -So this later and later can slope. So on multiplication 8.59 and 2.125 we get the value 1.07 so 1.07 mall of sodium chloride. So therefore the correct answers to the moles of sodium chloride from all of sodium chloride that is equal to 1.07 mol.
Detailed explanation-4: -Therefore, 101.1 grams of KNO3 K N O 3 is needed to make 2.00 L of a 0.500 M solution.
There is 1 question to complete.