LABORATORY REVIEW
MOLECULAR BIOLOGY
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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30
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60
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90
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10
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Detailed explanation-1: -But three DNA letters provide more than enough combinations to code for all twenty amino acids. So three was the answer. It was a triplet code.
Detailed explanation-2: -So hence the answer to the question is 10 amino acids in turn can be generated using these 30 nucleotide gene sequence it.
Detailed explanation-3: -Four nucleotides together form almost 64 different combinations if taken three at a time. Out of these 64 combinations, if we remove 3 stop codons such as TAA and others, we are left with 61 combinations encoding for 20 different amino acids.
Detailed explanation-4: -While one might quickly calculate that 90 nucleotides/3 would yield a 30 amino acid sequence, it is important to remember that while the first 3 nucleotides will encode for an amino acid to start translation (methionine), the last 3 nucleotides do not.