LABORATORY REVIEW
MOLECULAR BIOLOGY
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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ACTGATGCC
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ACUGAUGCC
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TGACTACGG
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UGACUACGG
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Detailed explanation-1: -The sequence for AACGTAACG in mRNA molecule synthesized after transcription from a DNA strand shall be UUGCAUUGC. In an RNA strand, the genetic code follows the sequence of A-U, G-C, and T-A.
Detailed explanation-2: -The sequence of nucleotides in the mRNA molecule is read consecutively in groups of three. RNA is a linear polymer of four different nucleotides, so there are 4 × 4 × 4 = 64 possible combinations of three nucleotides: the triplets AAA, AUA, AUG, and so on.
Detailed explanation-3: -Solution: When a DNA strand with the sequence AACGTAACG is transcribed, the resultant sequence of the mRNA molecule synthesized is UUGCAUUGC. This is based on the paring of nitrogenous bases-adenine pairs with thymine (in DNA) and uracil (in RNA) and guanine with cytosine.